Answer:
The density of Lithium β is 0.5798 g/cm³
Explanation:
For a face centered cubic (FCC) structure, there are total number of 4 atoms in the unit cell.
we need to calculate the mass of these atoms because density is mass per unit volume.
Atomic mass of Lithium is 6.94 g/mol
Then we calculate the mass of four atoms;
⇒next, we estimate the volume of the unit cell in cubic centimeter
given the edge length or lattice constant a = 0.43nm
a = 0.43nm = 0.43 X 10⁻⁹ m = 0.43 X 10⁻⁹ X 10² cm = 4.3 X 10⁻⁸cm
Volume of the unit cell = a³ = (4.3 X 10⁻⁸cm)³ = 7.9507 X 10⁻²³ cm³
⇒Finally, we calculate the density of Lithium β
Density = mass/volume
Density = (4.6097 X 10⁻²³ g)/(7.9507 X 10⁻²³ cm³)
Density = 0.5798 g/cm³
The microbial growth medium that would be used to sample for Fungi bacterial growth in sterile environment is : ( B ) Trypticase soy agar
<h3>What is a growth medium ?</h3>
A growth medium is a solid or liquid which is designed to support the growth of population such as microorganism through cell proliferation. A growth medium contains nutrients which support the growth of the microorganisms.
A growth medium which will support the growth of both fungi and bacteria growth is a Trypticase soy agar medium.
Hence we can conclude that The microbial growth medium that would be used to sample for Fungi bacterial growth in sterile environment is : Trypticase soy agar
Learn more about Growth medium : brainly.com/question/26298859
Answer:
[Y₂] = 31.25M
Explanation:
Based on the chemical reaction:
2X(g) + Y2(g) ⇌ 2XY(s)
We must define the equilibrium constant, K as:
K = 20 = 1 / [X]²[Y₂]
<em>Where</em> [X] and [Y₂]<em> are the equilibrium concentrations of each gas.</em>
<em />
If [X] = 4.0x10⁻²M:
20 = 1 / [4.0x10⁻²M]²[Y₂]
0.032 = 1 / [Y₂]
<h3>[Y₂] = 31.25M</h3>
Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.