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OLEGan [10]
3 years ago
7

Given 4.20 x 1022 molecules of He gas, what mass of He do you have?

Chemistry
1 answer:
kap26 [50]3 years ago
6 0
<h3>Answer:</h3>

0.279 g He

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.20 × 10²² molecules He

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of He - 4.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 4.20 \cdot 10^{22} \ molecules \ He(\frac{1 \ mol \ He}{6.022 \cdot 10^{23} \ molecules \ He})(\frac{4.00 \ g \ He}{1 \ mol \ He})
  2. Multiply/Divide:                                                                                               \displaystyle 0.278997 \ g \ He

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.278997 g He ≈ 0.279 g He

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The partial atmospheric pressure (atm) of hydrogen in the mixture is 0.59 atm.

<h3>How do we calculate the partial pressure of gas?</h3>

Partial pressure of particular gas will be calculated as:

p = nP, where

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  • n is the mole fraction which can be calculated as:
  • n = moles of gas / total moles of gas

Moles will be calculated as:

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Moles of Hydrogen gas = 2.02g / 2.014g/mol = 1 mole

Moles of Chlorine gas = 35.90g / 70.9g/mol = 0.5 mole

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Partial pressure of hydrogen = (0.6)(748) = 448.8 mmHg = 0.59 atm

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So for the production of 77.4 L water 90.3 L oxygen is required.

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