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bixtya [17]
3 years ago
6

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

nd the probability of x successes given the probability p of success on a single trial. Round to three decimal places. n = 4, x = 3, p =
Mathematics
2 answers:
Margarita [4]3 years ago
4 0
<span>Let X be the number of success in n trials. X has the binomial distribution with n = 4 trials and success probability p = 0.1666667 .</span>
elixir [45]3 years ago
3 0

Answer: 0.121

Step-by-step explanation:

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Step-by-step explanation:

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I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

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Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

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3 years ago
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First-person to answer with an Explanation get Brainliest
andrew11 [14]

Answer:

1) Yes, 1/2 and 2

2) b=1/2 × t

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Step-by-step explanation:

1) Yes, because <em>every</em> package of a toy equals 2 batteries. The constant of proportionality is 1/2 and 2 because 1 ÷ 2 = 1/2 and 2 ÷ 1 = 2 (amount of toys divided by amount of batteries and vice versa)

2) b = 1/2t, because for every battery, there is 1/2 a toy.

t = 2b, because for every toy, there are 2 batteries

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7 0
2 years ago
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