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3 years ago

Dont need too do question A

Mathematics

1 answer:

Brut [27]3 years ago

8 0

Answer:

B- 6x(x+2)

C- 3x( x(squared) -3)

4x(squared) (7x+1)

Step-by-step explanation:

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In a circle, area and circumference can be found using the formulas A=(pi)r^2 and C=2(pi)r, respectively, Write a formula for A

AURORKA [14]

Answer:

$A = \dfrac{C^2}{4\pi}$

Step-by-step explanation:

Given that

Area of a circle $A=\pi r^2$

Circumference of the circle $C = 2 \pi r$

Let us re-write the equation of area of circle:

$A=\pi r^2$

$A = \pi \times r \times r$

Multiplying and dividing with 2:

$A = \dfrac{2\pi r}{2} \times r\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C}{2} \times r\\\text{Multiplying and dividing by } 2\pi:\\\Rightarrow A = \dfrac{C}{2} \times \dfrac{2\pi r}{2\pi}\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C \times C}{4 \pi}\\\Rightarrow A = \dfrac{C^2}{4 \pi}$

Hence, <em>A</em> in terms of <em>C</em> can be represented as:

$A = \dfrac{C^2}{4\pi}$

4 0

3 years ago

Which quadratic equation has solutions x=8 and x=−1?

andrezito [222]

There are two ways you can do this

$Using the formula$

${x}^{2} - (sum \: of \: roots)x + poduct \: of \: roots = 0$

${x}^{2} - (8+-1)x + - 1 \times 8 = 0$

${x}^{2} - 7x - 8 = 0$

$Working backwards$

$x = 8 \: or \: x = - 1$
$\Rightarrow x-8=0 \: or \: x+1=0$

$\Rightarrow (x-8)(x + 1)=0$
$\Rightarrow {x}^{2} + x -8x - 8 = 0$
$\Rightarrow {x}^{2} - 7x - 8 = 0$

7 0

3 years ago

Factor the polynomial completely x^2-x-20

Strike441 [17]

Answer:

(x − 5) (x + 4)

Step-by-step explanation:

x² − x − 20

Factor using AC method:

1 × -20 = -20

Factors of -20 that add up to -1: -5 and 4

Divide by 1 and reduce: -5/1 and 4/1