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Alja [10]
3 years ago
8

What is the coefficient of the term of degree 2 in the polynomial below? x^6+3-2x^2+4x^7-4x a. -2 b. 3 c. -4 d. 4

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0
We have that
<span>x^6+3-2x^2+4x^7-4x

we know that 
</span><span>the term of degree 2 in the polynomial is -2x</span>² 
<span>and the coefficient of the term of degree 2 is (-2)

the answer is option a) -2</span>
Pavel [41]3 years ago
7 0

Answer:

a. -2

Step-by-step explanation:

The given polynomial is

x^6+3-2x^2+4x^7-4x

We rewrite the polynomial in standard form to obtain;

4x^7+x^6-2x^2-4x+3

The term of degree 2 in the polynomial is -2x^2.

The coefficient of this term is the constant that is multiplying x^2 which is -2

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3 years ago
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In-s [12.5K]

Answer:

Hello! Your answer would be, C) Divide by 2

Step-by-step explanation:

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2 years ago
Easy variable question pls help
svet-max [94.6K]

Answer:

z = -4 1/2

Step-by-step explanation:

1. First change the mixed fractions to improper fractions so it's easier

\frac{16}{5\\}/(z-\frac{1}{2}) = \frac{8}{3}/(z+\frac{1}{3})

2. Simplify

\frac{32}{5(2z-1)} = \frac{8}{3z+1}

3. Cross multiply

32(3z+1) = 5(2z-1) * 8

4. Simplify again (distributive property)

32(3z+1) = 40(2z-1)

5. Distributive property

32(3z+1) -> 96z+32  

40(2z-1) -> 80z-40

96z+32=80z-40

6. Subtract 32 from both sides

96z+32-32 = 80z-40-32

7. Simplify

96z = 80z-72

8. Subtract 80 from both sides

96z-80z=80z-72-80z

9. Simplify

16z=-72

10. Divide both sides by 16

\frac{16z}{16}=\frac{-72}{16}

11. Simplify

z=-\frac{9}{2} -> also = -4\frac{1}{2}

Sorry if it was too long but hope this helps! :)

And also try using symbolab cuz it gives step by step explanations it's really good!

7 0
2 years ago
(-5q^2 + 6q + 7) - (-q^2 + 4q)
beks73 [17]

Steps to solve:

(-5q^2 + 6q + 7) - (-q^2 + 4q)

~Distribute the left side

-5q^2 + 6q + 7 + q^2 - 4q

~Combine like terms

-4q^2 + 2q + 7

Best of Luck!

5 0
3 years ago
Read 2 more answers
X&gt;-3 ; (-4,3) Tell wether this is the solution of the inequality.
IceJOKER [234]
Not sure what you mean by solution since that’s already simplified and inequalities don’t hav coordinate points as solution.
But -4<-3 so that point wouldn’t go into the “shaded area” of that inequality.
Hope this helps
3 0
3 years ago
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