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QveST [7]
3 years ago
7

Which expression is equivalent to -2.8x-6.3

Mathematics
1 answer:
wariber [46]3 years ago
4 0

Answer:

-0.7(4x+9)

Step-by-step explanation:

-2.8x-6.3=-0.7(4x+9)

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A large company put out an advertisement in a magazine for a job
vova2212 [387]

Answer:

<em>C(19)=12 responses</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is frequently used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function can be expressed as follows:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The company puts out an advertisement for a job opening. Initially, the company got 90 responses to the advertisement. Each day, the responses declined by 10%.

This is an example where the decay model can be used to calculate the responses to the advertisement at the day t.

The initial value is Co=90, the decaying rate is r=10% = 0.10. The model is written as:

C(t)=90\cdot(1-0.1)^t

Calculating:

C(t)=90\cdot(0.9)^t

We are required to calculate the number of responses at day t=19, thus:

C(19)=90\cdot(0.9)^{19}

C(19)=12 responses

8 0
3 years ago
What’s the 16th term?
kramer

Put 16 where n is, then do the arithmetic.

... a(16) = -6 + 3(16 -1)

... a(16) = -6 + 45

... a(16) = 39

8 0
3 years ago
Read 2 more answers
Find the quotient of -64 and -8.
scoundrel [369]
The answer is 8 because a negative number times or divide by a negative number the answer will be a positive number.
8 0
3 years ago
Read 2 more answers
Gran knitted many wash clothes for the school fundraiser. She sold 42 cloths at the sale. There were 11 washcloths left after th
defon

Answer:

53

Step-by-step explanation:

c=42+11

c=53

5 0
3 years ago
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 3 &,& -4~) &#10;%  (c,d)&#10;&&(~ 5 &,& 1~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby &#10;\begin{array}{llll}&#10;\textit{now let's multiply both}\\&#10;\textit{sides by }\stackrel{LCD}{2}&#10;\end{array}&#10;\\\\\\&#10;2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}&#10;\\\\\\&#10;\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
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