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True [87]
3 years ago
12

What’s the 16th term?

Mathematics
2 answers:
kramer3 years ago
8 0

Put 16 where n is, then do the arithmetic.

... a(16) = -6 + 3(16 -1)

... a(16) = -6 + 45

... a(16) = 39

Leona [35]3 years ago
6 0
The answer is 39 because you have to plug in 16 for (n-1). Then you do 16-1=15. Then you do 3(15) which is 45. Then you do -6+45=39.
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PLEASE HELP!!!! WILL GIVE 50 POINTS!!!!
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Answer:

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Step-by-step explanation:

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3m=2(4+x) solve for x
algol13
Simple.........

3m=2(4+x)

Simplify...

3m=2(4+x)

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Read 2 more answers
Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
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Nataliya [291]
0.2 x 40
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6 0
3 years ago
How many negative roots will this function have? f(x) = x^7 – 2x^4 + 7x^2 + 2x – 2<br> help plsss
Vikentia [17]

There are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n

We have a polynomial function:

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

\rm f(x) =\left(x+1\right)\left(x^6-x^5+x^4-3x^3+3x^2+4x-2\right)

Using the zero product property:

\rm \left x+1\right = 0 \ \ \ or \left x^6-x^5+x^4-3x^3+3x^2+4x-2\right = 0

After solving:

x = -1, x = -0.853, and x = 0.418 (using the graph method)

Thus, there are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

Learn more about Polynomial here:

brainly.com/question/17822016

#SPJ1

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