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erma4kov [3.2K]
4 years ago
8

What is 1/3 divided by 1/9​

Mathematics
2 answers:
vodka [1.7K]4 years ago
6 0

Answer:

3

Step-by-step explanation:

1/3  / 1/9 =

1/3 x 9 =

3

HACTEHA [7]4 years ago
6 0

Answer:

0.3333

Step-by-step explanation:

1/9 ÷ 1/3 = 0.3333 in decimal form.

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Which equation is represented in standard form?
Elden [556K]

Answer:

The second answer is in standard form of equation

3 0
3 years ago
decide whether enough information is given to prove that triangle XYZ is congruent to triangle JKL. If so, state the term you us
Dafna1 [17]

The information given to us shows that triangles XYZ and JKL is not enough to prove they are congruent by AAS, ASA, nor SAS.

<h3>The Triangle Congruence Theorems</h3>
  • Two triangles are congruent by the AAS congruence theorem if they both have two pairs of congruent angles and a pair of congruent non-included sides.
  • Two triangles are congruent by the ASA congruence theorem if they both have two pairs of congruent angles and a pair of congruent included sides.
  • Two triangles are congruent by the SAS congruence theorem if they both have two pairs of congruent sides and a pair of congruent included angles.

Thus, the information given to us shows that triangles XYZ and JKL is not enough to prove they are congruent by AAS, ASA, nor SAS.

Learn more about triangle congruence theorem on:

brainly.com/question/2579710

7 0
3 years ago
Can someone please give me the answer to this problem?
Alik [6]
X= 9/2, 15/2
decimal form: 4.5,-7.5
mixed number form: 4 1/2, -7 1/2
3 0
3 years ago
X/a+x/b=1<br>make x the subject of the formular​
monitta

Answer:

x = \frac{ab}{b+a}

Step-by-step explanation:

Given

\frac{x}{a} + \frac{x}{b} = 1

Multiply through by ab to clear the fractions

bx + ax = ab ← factor out x from each term on the left side

x(b + a) = ab ← divide both sides by (b + a)

x = \frac{ab}{b+a}

8 0
3 years ago
Please answer question three and four if you can :)<br> Show full working out ty;)
nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0
4 years ago
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