Please explain how to solve this thank you

Mathematics

1 answer:

kotegsom [21]3 years ago

5 0

What is the question

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The areas of two equilateral triangles are 27 yd2 and 75 yd2. Find the ratio of their perimeters.

Cloud [144]

If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25

If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5.

3 : 5; 3 : 5 <==ANSWER

8 0

4 years ago

Read 2 more answers

What is the answer 12 x 12

aleksandr82 [10.1K]

12 × 12 would equal to 144

Hope this helped! :D

8 0

3 years ago

Read 2 more answers

Yall just use me 4 points }:

Klio2033 [76]

Answer:

thx.

Step-by-step explanation:

3 0

3 years ago

Answer true and false please<br> thanks

Aleksandr [31]

Option a is true and others are false

6 0

3 years ago

Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12

miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

$\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

$\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4$

3 0

3 years ago