Probability that no zebras collide is 0.25
The zebras are represented as z1, z2 and z3.
Z1 to B, Z2 to C, and Z3 to A come first
Following that, z1 to C, z2 to A, and z3 to B =
Consequently, the likelihood of no collision is 2×1/8 = 0.25.
<h3>
What are the types of probability distributions ?</h3>
Discrete and continuous probability distributions are the two main categories in which probability distributions fall. There are numerous varieties of probability distributions within each category.
- The number of favorable outcomes of an event divided by the total number of possible outcomes of an event can be used to calculate the probability of an event.
- The likelihood of a sure or certain event is one.
- The likelihood of an impossibility is 0 (0).
- Every event has a probability between 0 and 1.
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Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
Answer:
bbhwhehwyayyquqysyegegegsgsgsgsusus
Step-by-step explanation:
vgsgahah z z zb
Answer:16
Step-by-step explanation:
8^(4/3)=(cube root of 8)^4=2^4=2×2×2×2=16