.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)
Answer:
5
Step-by-step explanation:
Let's first find the slope of the linear function represented by the table:
As we move from x = 4 to x = 6 *an increase of 2), y increases by 6 from -2 to +4. Thus, the slope of this line is m = rise / run = m = 6/2, or 3.
Now we compare the two slopes: -2 and 3.
The postive difference between them is 5. This is Answer B.
At this case it could be calculated like this: 7+5*20=107
Answer: C
Step-by-step explanation: your fast answer is C.
Answer:
-2
Step-by-step explanation:
