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hammer [34]
3 years ago
5

Write the equation in slope intercept form for the following graph. Please help.?

Mathematics
1 answer:
ladessa [460]3 years ago
6 0

Answer: y=Mx+b

so y=-2/3x+5

Step-by-step explanation:

slope you go down 2 right 3, y int is (0,5)

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Suppose that angles A and B are complementary angles, where A is 5 times
Alla [95]

Answer:

105

Step-by-step explanation:

Let the angle of B be x

According to the question,

5x+x=90

or, 6x=90

or, x=15

The angle of B is 15

The angle of A is (15*5)=75

The supplementary angle of A is

(180-75)=105

4 0
2 years ago
There are 250 students in the 6th grade 45% of the eat lunch in 4th period how many students eat lunch in 4th period?
horrorfan [7]

Answer: 112.5

Step-by-step explanation:

The question really is asking whats 45% of 250

1. Calculate 10% of the total

2. Calculate 5% of the total

3. Solve for 40% of the total

4. Add 5% of the total

1. 10% of 250

250 = 100%

*divide both sides by 10*

25 = 10%

2. 5% of 250

25 = 10%

*divide both sides by 2*

12.5 = 5%

3. 40% of 250

10% + 10% + 10% + 10% = 40%

25 + 25 + 25 + 25 = 40%

50 + 50 = 40%

100 = 40%

4. 45% of 250

100 = 40%

12.5 = 5%

100 + 12.5 = 40% + 5%

<em>112.5 = 45%</em>

7 0
2 years ago
10+ 6 has the same sum as 7+
Nata [24]
7 plus 9.  10 plus 6 gives you 16, as does 7 plus 9.
4 0
3 years ago
Read 2 more answers
If two angles are supplement of each other, then one of the angles must be acute
oksian1 [2.3K]

Answer:

this is true

Step-by-step explanation:

a supplementary angle adds up to 180 degrees. two accute angles would equal to around 90 and two obtuse angles would add up to more than 180. two right angles are perpendicular and they could work but since the question asks about acute and obtuse, its true that one angle must be acute and the other must be obtuse for it to add up to 180.

7 0
3 years ago
An object with a starting velocity of 15 m/s accelerates at 3 m/s2. How far does the object travel within 10 seconds?
Anna007 [38]

Answer:  300 m

<u>Step-by-step explanation:</u>

distance(s)=v_it+\dfrac{1}{2}at^2 \quad \text{where}\ v_i \text{is initial velocity, a is acceleration, t is time}

s=(15)(10)+\dfrac{1}{2}(3)(10)^2

  = 150 + 150

  = 300

6 0
3 years ago
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