All categories

3 years ago

Write the slope-intercept form of the equation of the line through the given points. (0,3) and (-4 -1)

Mathematics

1 answer:

Scilla [17]3 years ago

7 0

Answer:

Step-by-step explanation:

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-4, -1) and (0, 3) → b = 3.

Calculate the slope:

$m=\dfrac{3-(-1)}{0-(-4)}=\dfrac{4}{4}=1$

Therefore we have the equation:

y = 1x + 3

You might be interested in

A plumber had two pipes. The ratio of the length of the longer pipe to the

expeople1 [14]

Answer:

4.95m

Step-by-step explanation:

Let the length of longer and shorter pipe be x and y respectively..

given,

x/y=9/2...(i)

x-1.65=3y ...(ii)

in eqn ii..

x-1.65=3y

or, x/y - 1.65/y = 3

or, 9/2-1.65/y =3

or, 4.5-3 = 1.65/y

or, y=1.65/1.5

•°• y = 1.1m

now,

x/y = 9/2

or, x/1.1 = 4.5

x= 4.5×1.1

•°• x= 4.95m

thus, the length of the longer pipe is 4.95m

7 0

3 years ago

‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎

nevsk [136]

Answer:

x = 2 and x = 4

Step-by-step explanation:

The solution of the given equation is shown on the graph

<u>There are two intercepts with coordinates of</u>

(2, 2) and (4, -22)

<u>The x-coordinates are </u>

x= 2 and x= 4

Correct option is 3 or C.

7 0

3 years ago

Read 2 more answers

How would I find angle B for this bridge? What formula would I use?

astraxan [27]

The bridge attached is drawn according to given dimensions, and it doesn't look right. Please double check the given dimensions.

Calculations:
Horizontal part of bottom chord below the 70 degree triangle
= 15.1*cos(70) = 5.16 (which is a major prt of the 6.3 units.
Height of vertical pieces DF and EH
= 15.1*sin(70) = 14.19
Note that structurally, DF and EH do not help in reducing stress on the bridge, since they are perpendicular to the bottom chord.

Therefore
angle B = atan(14.19/(6.3-5.16))=85.41 degrees

I believe the whole geometry does not look right, esthetically, and structurally, since the compression members are much longer than the tension members in the middle. (The vertical members carry no force.)
If you can review the input data, or post a new question, I will be glad to help.