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Phantasy [73]
3 years ago
10

Fill in the blanks:

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

Answer:

8943=8\times 1000+9\times 100+4\times 10+3\times 1=8\times 10^3+9\times 10^2+4\times 10^1+3\times 1

So in blanks there will be 8, 9, 4, 3

Step-by-step explanation:

We have given that 8943=.....\times 1000+....\times 100+....10+....1=....10^3+....10^2+....10^1+....1

We have to fill the blanks

We know that 8\times 1000=8000

9\times 100

4\times 10

3\times 1

When we add all then

8000+900+40+3=8943

So in the blanks there will be 8 , 9, 4 , 3

We also know that 8000=8\times 10^3

900=9\times 10^2

40=4\times 10^1

3\times 1=3

So 8943=8\times 1000+9\times 100+4\times 10+3\times 1=8\times 10^3+9\times 10^2+4\times 10^1+3\times 1

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Answer:

chocolate chip cookie first: 15 ways

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chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

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Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

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