Does anyone know how to do geometry

Total number of faculty is 136. There are 6 professors to every 11 lecturers. How many professors are there

laila [671]

Answer:

The Total number of Professors = 48

Step-by-step explanation:

Given as,

The total number of Faculty = 136

And the Ratio of Professors to Lecturers = 6 Ratio 11

Now According to question

Professors : Lecturers = 6 : 11

So, Let the Number of Professors = 6x

And The Number of Lecturers = 11x

∴ 6x + 11x = 136

Or, 17x = 136

Or, x = $\frac{136}{17}$ = 8

Hence, the number of Professors = 6 × 8 = 48 Answer

3 0

3 years ago

What is thirty-seven and nine tenths written in expanded form

xeze [42]

37.9 equals 30+7+.9 you should try to put in number form so you know what you're dealing with

3 0

3 years ago

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What is the average rate of change for h(t) between t=0 and t=2

nordsb [41]

Part a: Option D 18 feet per second

Part b: increasing

Solution:

Height $h(t)=-16 t^{2}+50 t+3$

Part a: To find the average rate of change for h(t) between t = 0 and t = 2.

Substitute t = 0 in h(t).

$h(0)=-16 (0)^{2}+50 (0)+3$

h(0) = 3

Substitute t = 2 in h(t).

$h(2)=-16 (2)^{2}+50 (2)+3$

h(2) = 39

Average rate of change formula:

$$=\frac{h(b)-h(a)}{b-a}$

Here, a = 0 and b = 2.

$$=\frac{h(2)-h(0)}{2-0}$

$$=\frac{39-3}{2}$

$$=\frac{36}{2}$

= 18

Average rate of change = 18 feet per second

Option D is the correct answer.

Part b:

This means height of the ball is increasing for 0 < x < 2.

6 0

2 years ago

WORTH 100 POINTS!

zzz [600]

Answer:

7miles

equations shown in work image below

work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)

:) please give a heart for thanks

and brainliest crown :)

Step-by-step explanation:

For both d=r*t

Each bikes to others house and leave at the same time so for Tony,

11 = 30*t

t= 11/30 hours

for Gerry,

11 = 25*t

t= 11/25 hours

Comparing these, with LCD,

Tony's time is 55/150

Gerry's time is 66/150

So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.

Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.

We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150

5 0

3 years ago

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Suppose a researcher is surveying four subjects: subject A, subject B, subject C, and subject D. Subject B wants to impress the

Lina20 [59]

Answer:

Subject B.

Step-by-step explanation:

It is given that,

There are total four subjects, namely A, B, C and D.

Out of these four subjects, we have, Subject B wants to impress the researcher above everyone while the other subjects do not care.

Since, Subject B wants to impress the researcher, they would want to use any means as possible so that the researcher gets amazed by them.

For this, it is highly possible that they will start answering questions in a way that makes them impressive, which would lead them to not answer questions honestly.

While the other subjects do not care whether the researcher is impressed, this will make them give the answer honestly.

Hence, Subject B is least likely to answer the questions honestly.

3 0

3 years ago

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