a. By the chain rule,
h'(x) = f'(g(x)) * g'(x)
h'(1) = f'(g(1)) * g'(1) = f'(1) * 1 = 3
b. I suspect there's a typo here somewhere, but if you really mean j(x) = f(x), and you're only supposed to find j(1), then
j(1) = f(1) = 2
Possibly you're supposed to instead find j'(1), in which case
j'(1) = f'(1) = 3
Or maybe j is defined like
j(x) = 1/f(x)
in which case the chain rule gives
j'(x) = -f'(x)/f(x)^2
j'(1) = -f'(1)/f(1)^2 = -3/2^2 = -3/4
c. By the chain rule,
k'(x) = g'(x)/g(x)
k'(1) = g'(1)/g(1) = 5/1 = 5
The congruence of the 2 triangles can be proved, angle C is common , CD is common, CA = CB, THEN the 2 triangles are congruent, the 2 triangles are equal so AD = DB hence CD bisects AB.
AND just that a attitude does not divides a line into equal half's, in an obtuse angle triangle the altitude is outside, only the median can divide a line into 2 equal half's or a triangle
hope this helps if this did Pls like and have any doubts ask me in the comments section, feel free
12in = 1 foot
3 feet = 1 yard
36in = 1 yd
36x2 = 72in/6=12x20 = 240 cents
$2.40
<span>I think the answer would be:
B) y= 4 cos 2 theta</span>
Answer:
Hi!
I see that you are new. Next time, it might be helpful to show us a picture, so we know how to help!
I think your answer might be similarity theorem though.
~CoCo
