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Ivahew [28]
3 years ago
10

What are these fractions in simplest form?

Mathematics
1 answer:
Anton [14]3 years ago
8 0
\frac{16y^{3}}{20y^{4}} =  \frac{4}{5y}
\frac{6xy}{16y} =  \frac{3x}{8}
\frac{abc}{10abc} =  \frac{1}{10}
\frac{mn^{2}}{pm^{5}n} =  \frac{n}{pm^{4}}
\frac{12h^{3}k}{16h^{2}k^{2}} =  \frac{3h}{4k}
\frac{8x}{10y} =  \frac{4x}{5y}
\frac{24n^{2}}{28n} =  \frac{6n}{7}
\frac{30hxy}{54kxy}  =  \frac{5h}{9k}
\frac{5jh}{15jh^{3}} =  \frac{1}{3h^{2}}
\frac{20s^{2}t^{3}}{16st^{5}} =  \frac{5s}{4t^{2}}
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Answer:

x=10

m=3

Step-by-step explanation:

The angles are the same since the sides are the same length (isosceles triangle)

55 = 5x+5

Subtract 5

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