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Ivahew [28]
3 years ago
10

What are these fractions in simplest form?

Mathematics
1 answer:
Anton [14]3 years ago
8 0
\frac{16y^{3}}{20y^{4}} =  \frac{4}{5y}
\frac{6xy}{16y} =  \frac{3x}{8}
\frac{abc}{10abc} =  \frac{1}{10}
\frac{mn^{2}}{pm^{5}n} =  \frac{n}{pm^{4}}
\frac{12h^{3}k}{16h^{2}k^{2}} =  \frac{3h}{4k}
\frac{8x}{10y} =  \frac{4x}{5y}
\frac{24n^{2}}{28n} =  \frac{6n}{7}
\frac{30hxy}{54kxy}  =  \frac{5h}{9k}
\frac{5jh}{15jh^{3}} =  \frac{1}{3h^{2}}
\frac{20s^{2}t^{3}}{16st^{5}} =  \frac{5s}{4t^{2}}
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c. x=6

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Complete the division. The quotient is 3x2 + x + .
andriy [413]

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3 years ago
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The function h(t)=−16t2+7t+63 represents the height of a t-shirt launched from a t-shirt cannon after t seconds. a. Write an equ
Fittoniya [83]

Answer:

(a)\ -16t^2 + 7t + 63=0

(b)\ t = 2.215

Step-by-step explanation:

Given

h(t) = -16t^2 + 7t + 63

Solving (a): Equation when it hits the ground.

This means that h(t) = 0

So, we have:

h(t) = -16t^2 + 7t + 63

-16t^2 + 7t + 63=0

Solving (b): The value of t in (a)

-16t^2 + 7t + 63=0

Using quadratic formula, we have:

t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

This gives:

t = \frac{-7 \± \sqrt{7^2 - 4*-16*63}}{2*-16}

t = \frac{-7 \± \sqrt{49+ 4032}}{2*-16}

t = \frac{-7 \± \sqrt{4081}}{-32}

t = \frac{-7 \± 63.88}{-32}

Split

t = \frac{-7 + 63.88}{-32}; or\ t = \frac{-7 - 63.88}{-32}

t = \frac{56.88}{-32}; or\ t = \frac{-70.88}{-32}

t = -1.7775; or\ t = 2.215

Time can't be negative; So:

t = 2.215

7 0
2 years ago
Explain please and tell me how to do it ?
SCORPION-xisa [38]

The trick to calculating the area here is to subdivide the diagram into smaller parts. For example, there's a 3 cm-by-3cm square. The rectangle is 4 cm by 8 cm.. The triangle has a base of 5 cm and a height of 3 cm.

Total area = area of square + area of rectangle + area of triangle

= 9 cm^2 + 32 cm^2 + (1/2)(5 cm)(3 cm)

= (9 + 32 + 7.5) cm^2

= 48.5 cm^2 (total area of figure)

8 0
3 years ago
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