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3 years ago

3.1(p - 2.7) simplified:

Mathematics

2 answers:

Mashcka [7]3 years ago

7 0

3.1(p - 2.7) simplified:= 3.1p-8.37

Dovator [93]3 years ago

4 0

Answer:

3.1x - 8.37

Step-by-step explanation:

Multiply each term in the parentheses by 3.1

3.1x - 3.1 x 2.7

Multiply the numbers to get 3.1x - 8.37

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How did they figure out the answer was 4 for the fraction problem solving. There are 36 people in the Newtown Hiking Club. 2/3 o

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Step-by-step explanation:

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3 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

Need anyone’s help with this APEX question! Much appreciated!

VMariaS [17]

Answer:

The correct answer option is D. (x - 7) + 2.

Step-by-step explanation:

We are to determine whether which of the given options best describe the English expression:

'two more than the quantity of a number minus seven'

We can break this expression into smaller chunks to make it easier to translate.

1. two more than ---> +2

2. the quantity of a number ---> suppose the number to be 'x'

3. number minus 7 ---> (x - 7)

Combining these, we get (x - 7) + 2 so the correct answer option is D.

7 0

3 years ago

Read 2 more answers

Order these numbers from least to the greatest, 47/10,4.606,4+13/20,4.64

exis [7]

Answer:

From lowest to highest, the numbers would follow the following order:

1) 4.606, 2) 4.64, 3) 4 + 13/20, 4) 47/10.

Step-by-step explanation:

Given that the numbers 47/10, 4.606, 4 + 13/20 and 4.64 are presented, to order these from lowest to highest, the following calculations must be performed:

47/10 = 4.70

4,606

4 + 13/20 = 4 + 0.65 = 4.65

4.64

Therefore, from lowest to highest, the numbers would follow the following order:

1) 4.606, 2) 4.64, 3) 4 + 13/20, 4) 47/10.

6 0

3 years ago