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nika2105 [10]
3 years ago
15

PLS help ill give 50 points to the person who answers correctly The instructions of an art project tell students to cut a piece

of paper into a quadrilateral with two pairs of congruent sides The instructions of an art project tell students to cut a piece of paper into a quadrilateral with two pairs of congruent sides. If all of the students follow the instructions, each paper will be Its one of the following a rectangle a parallelogram an isosceles trapezoid of no guaranteed classification
I have another question below that gives 50 points
Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

no guaranteed classification

Step-by-step explanation:

We know that the quadrilateral has two pairs of congruent sides. Both a rectangle and a parallelogram have two pairs of congruent sides. The difference between them is their angles. But we don't know anything about the angles in the figure, so we cannot know which kind it is.

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PLEASE HELP! Which points lie in the second quadrant? Check all that apply?
nevsk [136]

Answer:

is there picture?

Step-by-step explanation:

3 0
3 years ago
The height of a building in a drawing is 15 inches if the actual height of the building is 165 feet find the scale factor of the
Elenna [48]

Answer:

The scale is 11 feet per one inch.

Step-by-step explanation:

\frac{165feet}{15inches} = 11feet / inch

3 0
2 years ago
A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s
Setler [38]

Answer:

310\text{ feet and }210\text{ feet}

Step-by-step explanation:

GIVEN: A farmer has 520 \text{ feet} of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 310 \text{ feet}.

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be x and y

perimeter of rectangular pen =2(x+y)=520\text{ feet}

                                                x+y=260

                                               y=260-x

area of rectangular pen =\text{length}\times\text{width}

                                       =xy

putting value of y

=x(260-x)

=260x-x^2

to maximize \frac{d \text{(area)}}{dx}=0

260-2x=0

x=130\text{ feet}

y=390\text{ feet}

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen =310\text{ feet}

                              width of rectangular pen =210\text{ feet}

Maximum area of rectangular pen =310\times210=65100\text{ feet}^2

Hence maximum area of rectangular pen is 65100\text{ feet}^2 and dimensions are 310\text{ feet and }210\text{ feet}

5 0
3 years ago
Need answer asap pls...........
astraxan [27]
D I’m pretty sure. i counted all boxes and it equaled to 26
8 0
3 years ago
Read 2 more answers
Please answer this correctly without making mistakes
Gekata [30.6K]

Answer:

16

Step-by-step explanation:

The distance is given by

d = sqrt( (x2-x1) ^2 + ( y2-y1) ^2)

Since the x values are the same

d = sqrt(  ( y2-y1) ^2)

d = sqrt(  (( -6 - 10)^2))

d =  sqrt((-16) ^2)

d = 16

We can also just find the number of squares between the points since the x value is the same.

10 - -6

10+6

16

4 0
3 years ago
Read 2 more answers
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