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3 years ago

The coordinates of the vertices of a triangle are (−3,2), (0,−3), and (−4,−2).

Mathematics

1 answer:

sergeinik [125]3 years ago

6 0

The perimeter of the triangle, rounded to the nearest tenth, is 8.5 units.

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Which strategy can be used to multiply 6 x 198 mentally?

djverab [1.8K]

The box method or latitude or longitude.

8 0

2 years ago

Balance the equation

loris [4]

On the right side, there are

• 2•2 = 4 atoms of Nb

• 2•5 = 10 atoms of O

so among the reactants on the left, the reaction is balanced as

4 Nb + 5 O₂ → 2 Nb₂O₅

7 0

2 years ago

A spinner is divided equally into four colors, red, green, yellow and blue. Find the sum of the probabilities of spinning red, g

grandymaker [24]

Probability=number of specific outcomes / total number of possible outcomes...

Since they want to know the probability of getting all of the colors the probability is just one.

The sum of all probabilities is always equal to one. In this case:

1/4+1/4+1/4+1/4=1

5 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

-2 (6-x)+4x = 8 (2x+5)

Snezhnost [94]

-26 over 5

-26/5

hope this helps!

use photo math its a free app

3 0

3 years ago