<span>0.04285714285 this is your answer </span>
To solve for x, you need to isolate/get the variable "x" by itself in the equation:
3x - 3(x + 1) = 3 Distribute/multiply -3 into (x + 1)
3x + (-3)x + (-3)1 = 3
3x - 3x + 1 = 3
1 = 3
Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3
The answer is = (x + 5y) (x + 7y)
Break the expression into two groups.
x^2 + 12xy + 35y^2
(x^2 + 5xy) (7xy + 35^2)
Factor out x from x^2 + 5xy: x(x + 5y)
Factor out 7y from 7xy + 35y^2: 7y(x + 5y)
=x(x + 5y) + 7y(x + 5y)
Next, factor out the common term (x+ 5y).
Answer = (x + 5y) (x + 7y)
Answer:
4. H0: u1= u2 Ha; u1≠ u2
5. The smaller value of p supports the null hypothesis.
Step-by-step explanation:
4. The null and alternate hypotheses are
H0: u1= u2 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1≠ u2 i.e there a difference between the mean pinch strengthof the two surgeries
It can be written like this as well
H0: u1 -u2= 0 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1 -u2≠ 0 i.e there a difference between the mean pinch strengthof the two surgeries
Part 5. The test having a p- value less than 0.05 tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.
The smaller value of p supports the null hypothesis.
