I believe you meant:
If the average, mode, and range of 5 different numbers are all 8, find the sum of all possible values and the second largest number
Answer:
Sum of all possible values = 40
Second largest number= 8
Explanation:
Since our mean, mode, and range is 8, our sum is 40 and our second largest number is 8.
The sum of all the numbers is 40 since our mean is 8 and there are 5 numbers(8×5)
To find possible values, we already know the mode is 8 and so we know 8 must appear more than once. If we have 8 twice then we are left with 24(sum is 40). We have 3 numbers left and the range is 8 so we must have a maximum number and minimum number that has a difference of 8 and a third number, all adding up to 24(sum left). Within 24, only 12-4+8 satisfies the condition, hence our numbers are: 4,8,8,8,12.
Answer:
the top answer
Step-by-step explanation:
right hand Riemanns are an over approximation, so it would include higher number sets.
Total students in class-60
1/12 students absent- 1/12*60=5
Students present in the class- 60–5=55.
the answer is 55
There's a distinction between the <em>address </em>of the cell and the <em>value</em> it contains, and the difference in this problem lies in that distinction. The <em>contents</em> of cell 5 are the value 8, so moving that to cell number 6 would set its value to 8 as well, which is clearly different from the value 5.
