3 years ago

Find the product. (-2x ^2) ^3 -3x

Mathematics

2 answers:

klio [65]3 years ago

4 0

Answer:

$-8x^6-3x$

Step-by-step explanation:

$(-2x ^2) ^3 -3x$

we apply exponential property

distribute exponent 3 inside the parenthesis

(ab^m)^n= a^m * b^(mn)

$(-2x ^2) ^3 -3x$

$(-2^3x^6) -3x$

find the value of (-2)^3

-2^3 = -2*-2*-2=-8

$(-8x^6) -3x$

$-8x^6-3x$

ziro4ka [17]3 years ago

3 0

I hope this helps you

-8x^6-3x

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Step-by-step explanation:

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Read 2 more answers

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Xelga [282]

By giving just the radius and asking for the arc length of that circle your answer will be without math is 22
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But;

Let’s do same math!

Arc length = (()/360)⋅2⋅⋅
(
(
a
n
g
l
e
o
f
a
r
c
)
/
360
)
⋅
2
⋅
π
⋅
r

In this case angle of arc was not specified so: 360∘
∘
was used.

Arc length = ((360)/360)⋅2⋅⋅11
(
(
360
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⋅
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2 years ago

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stiv31 [10]

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Step-by-step explanation: