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aev [14]
3 years ago
5

Suppose you work for a marketing consulting firm and you are tasked to determine the proportion of Americans who respond positiv

ely to an ad your agency is testing for release. A survey is performed and you randomly select 134 respondents. You input your data into a statistical computing package (like Minitab) and you are given a 95% confidence interval of ( 0.2841 , 0.4472 ). You need to present these findings in the next departmental meeting. What is the correct interpretation of this interval
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer: A person can be 95% confident that the true population proportion of Americans who respond positively to an ad your agency is testing for release lies in ( 0.2841 , 0.4472 ).

Step-by-step explanation:

Interpretation for 95% confidence interval:

A person can be 95% confident that the true population parameter lies in it.

here , population parameter = Population proportion of Americans who respond positively to an ad your agency is testing for release.

Required interpretation: A person can be 95% confident that the true population proportion of Americans who respond positively to an ad your agency is testing for release lies in ( 0.2841 , 0.4472 ).

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Step-by-step explanation:

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8_murik_8 [283]

Answer:

P(45

And we can find this probability with the following difference:

P(-0.714

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.714

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of gallons of a population, and for this case we know the distribution for X is given by:

X \sim N(47.5,3.5)  

Where \mu=47.5 and \sigma=3.5

We are interested on this probability

P(45

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(45

And we can find this probability with the following difference:

P(-0.714

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5 0
3 years ago
Brenda’s bank offers car financing for 3, 4 or 5 years. If brenda chooses 5-year financing, how many monthly payments will she h
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The number of monthly payments Brenda will have will be given by:
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Step-by-step explanation:

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Step-by-step explanation:

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