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Talja [164]
3 years ago
13

Evaluate the radical. 1000−−−−√3

Mathematics
1 answer:
scoray [572]3 years ago
6 0
( 1000 )^1/3 
= ( 10 ^3 )^ 1/3

= ( 10 ) ^ 3 × 1/3

= 10

I hope this will useful to you.
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Find the domain of the graphed function?
MariettaO [177]

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<span>It’s B.</span>

7 0
4 years ago
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Simplify the expression 4(2x - 3y) ASAP
uranmaximum [27]

Answer:

8x - 12y

Step-by-step explanation:

4(2x-3y)

Distribute/multiply the 4 to everything in the parentheses

4 * 2x = 8x      4 * -3y = -12y

8x - 12y

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4 years ago
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10,000,000,000×200,000
Snowcat [4.5K]
10,000,000,000×200,000 = 2e+15
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3 years ago
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The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
What is the answer to this
blsea [12.9K]
Using the calculator it is 27.47 round off to 27.5
6 0
4 years ago
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