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Lelu [443]
3 years ago
12

Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to o

rbit at an altitude of 6390 km. Satellite B is to orbit at an altitude of 17300 km. The radius of Earth REis 6370 km. (a) What is the ratio of the potential energy of satellite B to that of satellite A, in orbit
Physics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

Pa = \frac{-GMeMa}{Re}

Pb = \frac{-GMeMb}{Re}

where

         Pa = Gravitational potential energy of satellite A

         Pb = Gravitational potential energy of satellite B

          G = gravitational constant

          Me = Mass of the earth

          Ma = Mass of satellite A

          Mb = Mass of satellite B

          Re = Radius of the earth

Pb/Pa = (-GMeMb/Re) / (-GMeMa/Re)

Pb/Pa =  Mb/Ma

Explanation:

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emmainna [20.7K]

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E = energy, h = planck constant, c= speed of light and

λ= wavelength.

From E=hf we can see that energy is directly proportional to frequency since h is a constant, this implies that as we move up the visible light spectrum, red light has the least frequency this accounting for the lowest energy while violet has the largest energy accounting for a very high energy.

Blue light is higher in the spectrum than red light.

This implies that blue light has more energy than red.

Visible light is part of the electromagnetic spectrum which implies that they all travel with the same speed of a constant value ( speed of light = 3* 10^8 m/s).

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This point nullifies the options thus making none of it correct.

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