During a drive by golfer Tiger Woods, the angular velocity of his club is zero at the top of his backswing and 30 rad/s at the b
ottom of his downswing just before impact with the ball. If his downswing lasts .30 s, what is the average angular acceleration of the club during the downswing?
1 answer:
You might be interested in
Answer:
Impedance = 93.75 ohms
Current = 1.81 A
Explanation:
Resistance = R = 80 ohms
Inductance = L = 0.2 H
Inductive reactance = XL = = ωL = (2πf) L
= 2 (3.14) (60)(0.2) = 75.398 Ohms
Capacitive reactance = 1 / ωC = 1/(2πf)C = 1 / [(2π)(60)(0.1 × 10⁻3)]
= 26.526 Ohms
Impedance = Z =
= = 93.747 ohms
Voltage = × 120 = 169.7056 V
Current = I = V ÷ R = (169.7056) ÷ 93,747 = 1.81 A