During a drive by golfer Tiger Woods, the angular velocity of his club is zero at the top of his backswing and 30 rad/s at the b
ottom of his downswing just before impact with the ball. If his downswing lasts .30 s, what is the average angular acceleration of the club during the downswing?
1 answer:
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Answer:
F= 224 N
Explanation:
Given that
mass ,m = 80 kg
Radius ,r= 5 m
speed at the top v= 8 m/s
The force at the top = F
Now by using the Second law of Newton's
Now by putting the values
Take g = 10 m/s²
F= 224 N
Therefore the force exerted by the track at the top position will be 224 N.
