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Ahat [919]
3 years ago
15

How much is 45+14567

Mathematics
2 answers:
Anna007 [38]3 years ago
6 0
14612 is the correct answer bruuuuhhhhhhh
alisha [4.7K]3 years ago
3 0
14612 is the answer to your math problem. This is so easy. just use a calculator.
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neptune is 4,498,252,900 kilometers from the sun. Which distance is 200,000,000 kilometers closer to the sun?
Virty [35]
The average distance of Neptune from the Sun is 2,795,084,800 miles or 4,498,252,900 kilometers. Because its orbit is elliptical, its distance from the Sun changes depending on where it is in its orbit. The closest Neptune gets to the Sun is 2,771,087,000 miles or 4,459,630,000 kilometers. The farthest it gets from the Sun is 2,819,080,000 miles or 4,536,870,000 kilometers.
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3 years ago
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Did he watch the whole movie
valentinak56 [21]
No, he has not watched the whole movie. The answer would be D. he only has 2/15 to watch. 

Hope I helped!
8 0
3 years ago
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The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
Help....!! I need to solve this simultaneous equation y=x-2 and y=3x+5 With working out if possible please....
Blababa [14]

Step-by-step explanation:

Y= x - 2. Y = 3x + 5

Putting value of y

x - 2 = 3x + 5

-2 - 5 = 3x - x

-7 = 2x

-7/2 = x

Putting value of x

Y = 3(-7/2) + 5

Y = - 10.5 + 5

Y = - 5.5

6 0
3 years ago
Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D
Ivahew [28]
Check the picture below.

\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D

\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D

7 0
3 years ago
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