Answer:
The probability that the sixth customer buys sour milk is
.
Step-by-step explanation:
The grocery store has a total of 10 cartons of milk.
The number of cartons of milk that are sour is, 2.
- If none of the sour cartons of milk were bought by the first 5 buyers, then the probability of this event is:
P (Both the sour cartons are available to be sold to the sixth customer)
= 
- If only one sour carton of milk is sold to the first 5 buyers then the probability is:
P (Only one sour cartons is available to be sold to the sixth customer)
= 
- If both the sour carton of milk is sold to the first 5 buyers then the probability is:
P (None of the sour cartons is available to be sold to the sixth customer)
= 
Compute the probability that the sixth customer buys sour milk:
= P (Both sour milk is available for the 6th customer) +
P (Only one sour milk is available for the 6th customer) +
P (None of the sour milk is available for the 6th customer)

Thus, the probability that the sixth customer buys sour milk is
.