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Strike441 [17]
3 years ago
13

In preparing a works cited list, you should

Computers and Technology
1 answer:
sergeinik [125]3 years ago
7 0
In preparing a works cited list, you should mlways follow MLA style. MLA style is the proper way to cite references<span> </span>
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colby lives a very career-driven lifestyle. he works long hours and enjoys making a lot of money by working overtime. after he a
just olya [345]

The role of being a father will decrease Colby’s income and decrease the career-driven nature of his lifestyle.

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If you wish to sign out of your Microsoft account, tap or click ____ on the ribbon to open the Backstage view and then tap or cl
lyudmila [28]
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3 years ago
X = 1 if (A = 1 OR B = 1) OR (A = 0 AND B = 1
Gnoma [55]

Answer:

For question a, it simplifies.  If you re-express it in boolean algebra, you get:

(a + b) + (!a + b)

= a + !a + b

= b

So you can simplify that circuit to just:

x = 1 if b = 1

(edit: or rather, x = b)

For question b, let's try it:

(!a!b)(!b + c)

= !a!b + !a!bc

= !a!b(1 + c)

= !a!b

So that one can be simplified to

a = 0 and b = 0

I have no good means of drawing them here, but hopefully the simplification helped!

4 0
3 years ago
How do you go about inserting additional worksheets into a workbook?
kicyunya [14]
The correct answer is D. All of the methods listed above are ways of inserting new sheets into a workbook.
6 0
3 years ago
Using the C language, write a function that accepts two parameters: a string of characters and a single character. The function
Sav [38]

Answer:

#include <stdio.h>

void interchangeCase(char phrase[],char c){

  for(int i=0;phrase[i]!='\0';i++){

      if(phrase[i]==c){

          if(phrase[i]>='A' && phrase[i]<='Z')

              phrase[i]+=32;

          else

              phrase[i]-=32;      

      }

  }

}

int main(){

  char c1[]="Eevee";

  interchangeCase(c1,'e');

  printf("%s\n",c1);

  char c2[]="Eevee";

  interchangeCase(c2,'E');

  printf("%s\n",c2);    

}

Explanation:

  • Create a function called interchangeCase that takes the phrase and c as parameters.
  • Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
  • If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
  • Inside the main function, test the program and display the results.
8 0
3 years ago
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