Answer:
The correct answer to the following question will be Option D (Homans sign).
Explanation:
To medicine, the symptom of Homans is considered a sign of thrombosis by some physicians. John Homans described Homans as an annoyance under the knee of the foot to 1941 after forced dorsification.
- Inspect the limbs for edema, pulse equality, and capillary refill.
- Check to sign Homans.
- Feel any warmth or redness along the Calf area.
- Bilateral calves should be equal in size and warmth.
- There must be no swollen, sore places, and when the woman is moving, there will be no pain in the calves.
Therefore, Option D is the right answer.
Answer:
False
Explanation:
Diversification involves increasing the reach of a particular software to meet the needs of different people. When a particular software is developed to provide multiple services for different individuals, it can be categorized as diversification but when the software is improved upon to meet the same users within a specific domain, the software can not be said to be diverse.
From our scenario, the operating system software is improved upon to handle the continuous changes in computer, this does not make the operating system software diverse, it just becomes better.
Explanation:
Hey there!
Here,
Given;

<u>Shift</u><u> </u><u>"</u><u>c"</u><u> </u><u>to</u><u> </u><u>right</u><u> </u><u>side</u><u>.</u>
<u>
</u>
<u>Divide</u><u> </u><u>"</u><u>k-c"</u><u> </u><u>by</u><u> </u><u>9</u><u>.</u>
<u>
</u>
<u>Therefore</u><u>, </u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>k-c</u><u>)</u><u>/</u><u>9</u><u>.</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
#include <iostream>
using namespace std;
int main()
{
cout << "N\t10*N\t100*N\t1000*N" << endl;
int x=1;
while(x<=5){
cout << x <<"\t"<< x*10 <<"\t"<<x*100 <<"\t"<< x*1000 << endl;
x++;
}
return 0;
}
Explanation:
Print the header, N 10*N 100*N 1000*N, using \t
Initialize the x as 1. It will be used to control the while loop
Create a while loop that iterates while x is smaller than or equal to 5
Inside the loop, print the required values. After printing, increment the value of x by 1