Answer:
rc length = 10 * 8pi/5
= 16pi
This is the circumference of the base
(a) 2pir = 16pi where r = radius of base
2r = 16
r = 8 cm
(b) 10^2 = h^2 + 8^2
h^2 = 100 - 64
= 36
h = 6 cm
Answer:
24
Step-by-step explanation:
PEMDAS: 15-14+23
1+23
24
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
2nd one is corect
60% is 93.49$ but u are getting 100$ discount so 2nd is ans
