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3 years ago

I NEED HELP PLEASE, THANKS! :)

Mathematics

1 answer:

marissa [1.9K]3 years ago

5 0

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

These are are parametric equations

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Find the slant height of a cone that has a diameter of 8 cm and a total surface area of 124(pi) cm^2

Morgarella [4.7K]

Answer:

The answer is 188

Step-by-step explanation:

because cm is 8 and cm has the exponent of 2 so that will equal 64 and 64 plus the area is 188

7 0

3 years ago

2. Express each of the following as a rational number in the form of p/q Where q≠0

ANTONII [103]

Step-by-step explanation:

We need to find each of the following as a rational number in the form of p/q

(a) (3/7)² (b) (7/9)³ (c) (-2/3)⁴

Solution,

(a) (3/7)²

$(\dfrac{3}{7})^2=\dfrac{9}{49}$

(b) (7/9)³

$(\dfrac{7}{9})^3=\dfrac{7\times 7\times 7}{9\times 9\times 9}\\\\=\dfrac{343}{729}$

$(\dfrac{-2}{3})^4=\dfrac{-2\times -2\times -2\times -2}{3\times 3\times 3\times 3}\\\\=\dfrac{16}{81}$

Hence, this is the required solution.

4 0

2 years ago

HELP PLEASEEE. I DONT UNDERSTAND

Shtirlitz [24]

Answer:

Step-by-step explanation:

So we have the equation:

$x^2-6x+58=0$

And we want to solve for x.

We can solve it by completing the square.

First, subtract 58 from both sides:

$x^2-6x=-58$

Divide the b term by 2 and square it:

$(-6)/2=-3\\(-3)^2=9$

So, add 9 to both sides:

$(x^2-6x+9)=-58+9$

On the left, the perfect square trinomial pattern. Add on the right. So:

$(x-3)^2=-49$

Take the square root of both sides:

$x-3=\pm \sqrt{-49}$

The square root of -49 is 7i:

$x-3=\pm 7i$

Add 3 to both sides:

$x=3\pm 7i$

So, our answer is D.

And we're done!

4 0

2 years ago

I need help lol. Find the lateral surface area of the figure to the nearest tenth.

Mekhanik [1.2K]

Answer:

101.9 sq ft

Step-by-step explanation:

The figure is missing: find it in attachment.

Here we want to find the lateral surface area of the figure, which is the sum of the areas of all faces.

We have in total 5 faces:

- 1 of them is rectangle with sizes (8.5 ft x 3.3 ft), so its area is

$A_1=8.5 \cdot 3.3 =28.1 ft^2$

- 1 of them is a rectangle with sizes (3.3 ft x 5.1 ft), so its area is

$A_2 = 3.3\cdot 5.1 =16.8 ft^2$

- 1 of them is a rectangle with sizes (6.8 ft x 3.3 ft), so its area is

$A_3 = 6.8\cdot 3.3 =22.4 ft^2$

- Finally, we have 2 triangular faces (top and bottom), so their area is

$A_T=\frac{1}{2}bh$

where

b = 5.1 ft is the base

h = 6.8 ft is the height (because the triangle is a right triangle)

So the area of the triangle is

$A_T=\frac{1}{2}(5.1)(6.8)=17.3 ft^2$

So the total lateral surface area of the figure is:

$A=A_1+A_2+A_3+2A_T=28.1+16.8+22.4+2(17.3)=101.9 ft^2$

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3 years ago

How do I solve this graph

Sunny_sXe [5.5K]

Plug in two values for x, say, 0 and 1.

Lets start with solving the equation when x=0.

y=2(0)-3
y=0-3
y=-3.

So, when x=0, y=-3. Graph (0, -3)

Next, x=1

y=2(1)-3
y=2-3
y=-1

So, when x=1, y=-1. Graph (1,-1)

Draw a line between the two points, and that should be your answer! Hope this helped :)

8 0

2 years ago

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