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Tems11 [23]
4 years ago
8

This answer pls help

Mathematics
1 answer:
serg [7]4 years ago
6 0
12 I think? I’m just guessing sorry.
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How to write (4f - 3 + 2g) - (-4g + 2) in standard form.
ANTONII [103]

Answer:

4f-5+6g

Step-by-step explanation:

Standard Form:4f-5+6g

(4f - 3 + 2g) - (-4g + 2)  REMOVE PARENTHESIS

4f-3+2g+4g-2 CALCULATE AND COMBINE LIKE TERMS

SOLUTION:4f-5+6g

8 0
3 years ago
Which of the following sets of numbers between 12 and 20 contains only prime numbers
kotykmax [81]
There is nothing "following", so an accurate answer is:. There's no such set on the list of choices you provided.

The prime numbers between 12 and 20 are 13, 17, and 19.
3 0
4 years ago
Read 2 more answers
Determine o valor dos termos desconhecidos nos triângulos abaixo:<br> HELPP
myrzilka [38]

Answer:

Option (B)

Step-by-step explanation:

By using the property of a triangle → " Sum of interior angles of a triangle is 180°"

Therefore, (4x - 40) + (x + 20) + x = 180°

(4x + x) + (-40 + 20) = 180°

5x - 20 = 180

5x = 180 + 20

5x = 200

x = 40

Therefore, value of x will be 40.

Option (B) will be the correct option.

5 0
3 years ago
4) If x-1/x=5, fand the value of x²+ 1/x²​
tangare [24]

Given:

\sf x\ -\ \dfrac{1}{x}\ =\ 5

To find:

\sf The\ value\ of\ x^2\ +\ \dfrac{1}{x^2}.

Answer:

\sf x\ -\ \dfrac{1}{x}\ =\ 5

Let's square the above expression.

\sf \bigg(x\ -\ \dfrac{1}{x}\bigg)^2\ =\ 5^2

According to the identities, (a - b)² = a² - 2ab + b². Using the same logic for the expression above,

\sf x^2\ -\ 2\ \times\ x\ \times\ \dfrac{1}{x}\ +\ \dfrac{1}{x^2}\ =\ 25\\\\\\x^2\ -\ 2\ +\ \dfrac{1}{x^2}\ =\ 25\\\\\\x^2\ +\ \dfrac{1}{x^2}\ =\ 25 + 2\\\\\\x^2\ +\ \dfrac{1}{x^2}\ =\ 27

Therefore, the value of x² + 1/x² is 27.

8 0
3 years ago
Brent conducted a survey in his school regarding whether students ride their bikes to school each day. he surveyed a random samp
Sonbull [250]
About 270 students bike yo school
8 0
3 years ago
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