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Mice21 [21]
2 years ago
5

Write an equation for each line.

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0

Answer:

Step-by-step explanation:

Equation of blue line:

blue line is parallel to y-axis

⇒ x = 5

Equation of green line:

Green line is parallel to x-axis.

y = 2

Equation of red line:

At y-intercept x = 0. Point on red line is (0,5)

So, y-intercept = 5

y = mx + b Here,  m is slope any b is y-intercept.

y = mx + 5

Now, choose any other point in red line. ((1,7)

Substitute this value in the above equation and we can find m

7 = m*1 + 5

7 - 5 = m

m = 2

y = 2x + 5

Equation of black line:

Black line and red line are parallel and so, they have same slope.

y = 2x + b

y-intercept (0,-6) ; b = -6

y = 2x - 6

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Rearrange the equation a = 1/2 b to make b the formula
Evgesh-ka [11]

Answer: b = 2a

Step-by-step explanation:

<u>Original equation</u>

a = (1/2) b

<u>Multiply 2 on both sides</u>

a * 2 = (1/2) b * 2

\Large\boxed{b=2a}

Hope this helps!! :)

Please let me know if you have any quesitons

8 0
1 year ago
Read 2 more answers
Juan fode his bike 2/3 mile to school,1/3 mile to the library,2/3 mile home far did he ride altogether
Viktor [21]

Answer:1 2/3

Step-by-step explanation:

2/3+1/3+2/3=5/3=1 2/3

7 0
3 years ago
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
it cost $45 to produce 2 calculators and $143 to produce 4 and $869 to produce 10 how much does it cost to produce 7 calculators
erica [24]

Answer:

210.50

Step-by-step explanation:

45/ 2 = 22.5

4 = 143

2= 45

+ 1 = 22.5

in total = 210.50

4 0
3 years ago
The gravitational force exerted by the planet Earth on a unit mass at a distance r from the center of the planet is:
jolli1 [7]

Answer:

Yes, F is a continuous function of r

Step-by-step explanation:

We are given that

When r<R

F(r)=\frac{GMr}{R^3}

r\geq R

F(r)=\frac{GM}{r^2}

Where M=Mass of the earth

R=Radius of earth

G=Gravitational constant

We have to find the function is continuous of r or not.

LHL

\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}

RHL

\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}

F(R)=\frac{GM}{R^2}

When a function is continuous at x=a

Then, LHL=RHL=f(a)

RHL==LHL=F(R)

Hence, the function is continuous of r.

8 0
3 years ago
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