2500 in standard form is 2.5 × 10³
Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
Answer:
He gets 42 visitors 4 weeks after starting to build his website.
He gets 10 new visitors per week.
Step-by-step explanation:
Equation for the number of visitors:
The equation for the number of visitors Timmy's new website receives after t weeks is:
In which b is the number of visitors rightly after he starts.
Timmy is building a new website. Right after he starts, he has 2 visitors.
This means that 
, so:
How many visitors does he get 4 weeks after starting to build his website?
This is v(4). So
He gets 42 visitors 4 weeks after starting to build his website.
How any new visitors does he get per week?
After 0 weeks:
After 1 week:
2 weeks:
After 2 week:
22 - 12 = 12 - 2 = 10
He gets 10 new visitors per week.
So the answer is, x1=-2, x2=9
x^2-7x=18
x^2-7x-18=0
x^2+2x-9x-18=0
x*(x+2)-9(x+2)=0
(x+2)*(x-9)=o
x+2=0
x-9=0
X=-2
X=9
I hope u understand!
What we know: A dozen costs 1.32; there are 12 in a dozen.
What we need to know: How much a restaurant makes selling 1 egg at 0.99.
First, find the value of one egg; you can do that by dividing the total cost (1.32) by the amount (12):
1.32 / 12 = 0.11 <-- The cost per egg is 11 cents. To find the profit of the restaurant, just subtract the cost from the price they sell it for:
0.99 - 0.11 = 0.88 <-- The profit the restaurant makes per egg is 88 cents.
Hope this helps.
