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nikitadnepr [17]
3 years ago
7

Jose and Franco were playing a video game if Jose score 782,076 points and Franco scored 811,968 point what is the difference be

tween the points scored
Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

29,892

Step-by-step explanation:

811,968-782,076

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What is the value of x in the equation 3/2(4x – 1) – 3x = 5/4 – (x + 2)?
Olegator [25]

i have attached a file you can see it from there.

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3 years ago
Ben weighs 140.8 pounds, and Jennifer weighs 117.7 pounds. How many more pounds does Ben weigh than Jennifer?
DENIUS [597]

Answer:

Ben weighs 23.1 lbs more than Jennifer.

Step-by-step explanation:

To find the difference between Ben and Jennifer's weight, you have to subtract the smaller number from the bigger number. In this case, subtract Jennifer's weight from Ben's weight. This would look like this: 140.8-117.8.

140.8-117.7=23.1

Therefore, Ben weighs 23.1 lbs more than Jennifer.

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3 years ago
HELP PLEASE IM BEGGING PLEASE PLEASE PLEASE
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Answer:

h - 18 = 67

Step-by-step explanation:

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3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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