I believe the range is the middle number so start from 63 then 46 then 53 then go back and forth until you get the middle number now after you get the middle number for the IQR add up both sides of the middle and / by the all the number on the left and right of the middle number
The phrase gives you an interval where the extremes are included.
The intervals may be indicated in several ways.
7.2 ≤ x ≤ 7.6
The correct answer to your question is 4/5th of a page
A number decreased by thirty seven or thirty seven less than a number
Answer:
Therefore, the inverse of given matrix is

Step-by-step explanation:
The inverse of a square matrix
is
such that
where I is the identity matrix.
Consider, ![A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%263%5C%5C3%266%5Cend%7Barray%7D%5Cright%5D)








Therefore, the inverse of given matrix is
