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jonny [76]
3 years ago
12

What is the root of -x^2+12x-32

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

x = 4, x = 8

Step-by-step explanation:

To find the roots equate to zero, that is

- x² + 12x - 32 = 0 ( multiply through by - 1 )

x² - 12x + 32 = 0

Consider the factors of the constant term (+ 32) which sum to give the coefficient of the x- term (- 12)

The factors are - 4 and - 8, since

- 4 × - 8 = + 32 and - 4 - 8 = - 12, thus

(x - 4)(x - 8) = 0

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x - 8 = 0 ⇒ x = 8

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Pleaseeeeeeeee answer if you do your the best at life!!!!!
jenyasd209 [6]

x+(-8)= -12

x-8= -12

x= -12+8

x=-4

-3 + x = 10

x=10+3

x=13

-2+x= -5

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