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Scilla [17]
3 years ago
12

What is the smallest distance between the origin and a point on the graph of:y=1/sqrt(2)*(x^2-8)

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0
What we are being asked here is to simply minimize distance. Also, note that we can write
f
(
x
)
=
√
x
as
y
=
√
x
.
Now, what is this "distance?" How do we find it? Well, if you think back to Algebra I or Geometry, you'll remember that the distance between two points
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
is given by:
√
(
y
2
−
y
1
)
2
+
(
x
2
−
x
1
)
2
. For example, the distance between the points
(
4
,
0
)
and
(
0
,
3
)
would be:
√
(
3
−
0
)
2
+
(
4
−
0
)
2
=
√
9
+
16
=
√
25
=
5
Ok, so what is
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
in our example?
(
x
1
,
y
1
)
is simple - it's just the point given in the problem,
(
4
,
0
)
. Because we don't know what
x
2
is, we'll just call it
x
for now. As for
y
2
, we don't know that either; and since
y
=
√
x
, we'll call it
√
x
.
Our formula then becomes:
√
(
√
x
−
0
)
2
+
(
x
−
4
)
2
=
√
(
√
x
2
)
+
x
2
−
8
x
+
16
=
√
x
+
x
2
−
8
x
+
16
=
√
x
2
−
7
x
+
16
We are being asked to minimize this distance, which we'll call
s
to make the following calculations easier. To minimize something, we have to take its derivative, so let's start there:
s
=
√
x
2
−
7
x
+
16
=
(
x
2
−
7
x
+
16
)
1
2

d
s
d
x
=
(
2
x
−
7
)
⋅
1
2
(
x
2
−
7
x
+
16
)
1
2
→
Using power rule and chain rule
d
s
d
x
=
2
x
−
7
2
√
x
2
−
7
x
+
16
Now we set this equal to
0
and solve for
x
:
0
=
2
x
−
7
2
√
x
2
−
7
x
+
16
0
=
2
x
−
7
x
=
7
2
This is known as the critical value, and it represents the
x
-value for which the function is minimized. All we need to do now is find the corresponding
y
-value, using the definition of
y
:
y
=
√
x
. Substituing
7
2
for
x
:
y
=
√
7
2

y
≈
1.87
And voila, the
y
-value. We can now say that the minimum distance between
f
(
x
)
=
√
x
and the point
(
4
,
0
)
(the place where these two are closest) occurs at
(
7
2
,
1.87
)
. For a little extra fun, we can use the distance formula to see what the actual distance between the points is:
s
=
√
(
1.87
−
0
)
2
+
(
7
2
−
4
)
2
≈
1.8
units
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Step-by-step explanation:

3 0
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The Department of Streets of a city has a budget of $1,962,800 for resurfacing roads and hiring additional workers this year. Th
Norma-Jean [14]

Answer:

d \large \frac{1,962,800-84,000m}{36,000}=

e \large 84,000m+36,000w=1,962,800

Step-by-step explanation:

Given the following :

Budgeted amount = $1,962,800

Cost of resurfacing a mile of 2- lane road = $84,000

Salary of additional worker = $36,000

Number of miles = m

Number of workers = w

equations that represents the relationship between the miles of 2-lane roads the department could resurface, m, and the number of new workers it could hire, w, if it the entire budget is spent ;

(Cost of a mile of 2-lane road * number of miles) = total budget

(84000m + 36000w) = 1,962,800

To make w, the subject of the formula :

36000w = 1962800 - 84000m

w = (1962800 - 84000m) / 36000

To make m, the subject of the formula :

84000m = 1962800 - 36000w

m = (1962800 - 36000w) / 84000

4 0
4 years ago
How many people were surveyed for the frequency table below?<br><br> 6<br> 25<br> 63<br> 8
Fantom [35]

Answer:

25 people were surveyed.

Step-by-step explanation:

Add up the frequency.

5 0
3 years ago
Read 2 more answers
Which of the following functions is graphed below?​
Harrizon [31]
You need to show the rest of the functions
5 0
3 years ago
If AC = 14, what is the measure of AD? Round your answer to the nearest hundredth.
nikklg [1K]

Part A

Answer: Choice D) \text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}

-----------------------------------------------

Explanation:

Let E be the intersection point of the diagonals. For any parallelogram, the diagonals bisect each other. This means that AE = EC = 2n+5 and it also means EB = DE = 4n-3

Focus on triangle AED. This triangle is a right triangle with angle AED as a 90 degree angle (any rhombus has its diagonals that are perpendicular to one another). The legs of this triangle are AE = 2n+5 and ED = 4n-3

Apply the pythagorean theorem to find hypotenuse AD

(\text{leg1})^2+(\text{leg2})^2 = (\text{hypotenuse})^2\\\\(\text{AE})^2+(\text{ED})^2 = (\text{AD})^2\\\\(\text{AD})^2 = (\text{AE})^2+(\text{ED})^2\\\\\text{AD} = \sqrt{(\text{AE})^2+(\text{ED})^2}\\\\\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}\\\\

This points to choice D as the final answer.

===========================================================

Part B

<h3>Answer:   7.07</h3>

-----------------------------------------------

Explanation:

If AC = 14, then half of this is AE = 7. The diagonals bisect each other, so they cut each other in half with E at the midpoint.

Since AE = 2n+5, we can solve for n like so

2n+5 = 7

2n = 7-5

2n = 2

n = 2/2

n = 1

Then we can find the length of AD

\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}\\\\\text{AD} = \sqrt{(2*1+5)^2+(4*1-3)^2}\\\\\text{AD} = \sqrt{(2+5)^2+(4-3)^2}\\\\\text{AD} = \sqrt{7^2+1^2}\\\\\text{AD} = \sqrt{49+1}\\\\\text{AD} = \sqrt{50}\\\\\text{AD} \approx 7.0710678\\\\\text{AD} \approx 7.07\\\\

Segment AD is roughly 7.07 units long. The other external sides of the rhombus (AB, BC and CD) are also this length because the four sides of any rhombus are the same length.

7 0
3 years ago
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