What we are being asked here is to simply minimize distance. Also, note that we can write f ( x ) = √ x as y = √ x . Now, what is this "distance?" How do we find it? Well, if you think back to Algebra I or Geometry, you'll remember that the distance between two points ( x 1 , y 1 ) and ( x 2 , y 2 ) is given by: √ ( y 2 − y 1 ) 2 + ( x 2 − x 1 ) 2 . For example, the distance between the points ( 4 , 0 ) and ( 0 , 3 ) would be: √ ( 3 − 0 ) 2 + ( 4 − 0 ) 2 = √ 9 + 16 = √ 25 = 5 Ok, so what is ( x 1 , y 1 ) and ( x 2 , y 2 ) in our example? ( x 1 , y 1 ) is simple - it's just the point given in the problem, ( 4 , 0 ) . Because we don't know what x 2 is, we'll just call it x for now. As for y 2 , we don't know that either; and since y = √ x , we'll call it √ x . Our formula then becomes: √ ( √ x − 0 ) 2 + ( x − 4 ) 2 = √ ( √ x 2 ) + x 2 − 8 x + 16 = √ x + x 2 − 8 x + 16 = √ x 2 − 7 x + 16 We are being asked to minimize this distance, which we'll call s to make the following calculations easier. To minimize something, we have to take its derivative, so let's start there: s = √ x 2 − 7 x + 16 = ( x 2 − 7 x + 16 ) 1 2
d s d x = ( 2 x − 7 ) ⋅ 1 2 ( x 2 − 7 x + 16 ) 1 2 → Using power rule and chain rule d s d x = 2 x − 7 2 √ x 2 − 7 x + 16 Now we set this equal to 0 and solve for x : 0 = 2 x − 7 2 √ x 2 − 7 x + 16 0 = 2 x − 7 x = 7 2 This is known as the critical value, and it represents the x -value for which the function is minimized. All we need to do now is find the corresponding y -value, using the definition of y : y = √ x . Substituing 7 2 for x : y = √ 7 2
y ≈ 1.87 And voila, the y -value. We can now say that the minimum distance between f ( x ) = √ x and the point ( 4 , 0 ) (the place where these two are closest) occurs at ( 7 2 , 1.87 ) . For a little extra fun, we can use the distance formula to see what the actual distance between the points is: s = √ ( 1.87 − 0 ) 2 + ( 7 2 − 4 ) 2 ≈ 1.8 units
The quantities are not proportional because the line of the graph is both passing through the origin. It might have been proportional if it was passing through the origin.