Answer:
Step-by-step Explanation:
Given:
∆UVW,
m < U = 33°
m < V = 113°
VW = u = 29 m
Required:
Area of ∆UVW
Solution:
Find side length UV using Law of Sines
U = 33°
u = VW = 29 m
W = 180 - (33+113) = 34°
w = UV = ?
Cross multiply
Divide both sides by sin(33) to make w the subject of formula
(rounded to nearest whole number)
Find the area of ∆UVW using the formula,
(to nearest tenth).
The answer to the question
Well, Brainly really doesn't like questions that are lifted straight out of exams, tests, or quizzes, so there's only so much I can say.
... You've GOT the formula for the height h at any time t .
... It TELLS you to find t when h=0.
... So write the equation
-16 t^2 + 32 t = 0
and then solve the equation to find t .
You'll find two solutions for t .
One of them is. t=0 .
This reveals the mind-blowing fact that the instant before the rocket was launched, at t=0, the rocket was on the ground.
The other solution for t will tell you how many seconds after launch the rocket is back on the ground.
Answer:
the answer is G) Change 30 to 3,000
Hey! When you ask a question there is a math equation option. Use that to scan the problem and it will give you your answer.
