Can someone read and answer the question please ?

Urgent help!!! I'll choose brainlest! Plsss

kipiarov [429]

A) volume equals = length x width x height
2.8m is the height
1.2m is the width
4.8m is the length
so 2.8m x 1.2m x 4.8m = 16.128m³ is your answer
b)1 cubic meter is 1000
2.8m = 2800L
1.2m = 1200L
4.8m = 4800L
so your going to add those up
2800L + 1200L + 4800L = 8800L is you answer

7 0

3 years ago

Read 2 more answers

What is the value of the expression 2m + m - 4(-2m +1-m) When m -8?

timama [110]

Answer:

The answer should be -124.

5 0

3 years ago

4 4/5 x 3 2/6 I don’t understand this pls help

klasskru [66]

Answer:

change to improper fraction

24/5 × 20/6=16 (you cross multiply)

4 0

2 years ago

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The math club makes 35 bars of laundry soap a week and sells these at $20 each before the soap could be sold , the pupils found

Svet_ta [14]

Answer:

Step-by-step explanation:

The math club makes 35 bars of laundry soap a week and sells these at $20 each. This means that the total number of bars of laundry soap made in a 4 week month would be

4 × 35 = 140 bars

If the pupils found that 6 bars were destroyed by mice, the total number of bars of soap left would be

140 - 6 = 134 bars

Therefore, the total sale at the end of a four week month would be

134 × 20 = $2680

7 0

3 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago