Answer:
( x + 2 ) and ( x - 11 )
Step-by-step explanation:
x² - 9x - 22 = 0
x² + 2x - 11x - 22 = 0
x ( x + 2 ) - 11 ( x + 2 ) = 0
( x + 2 ) ( x - 11 ) = 0
Factors of x² - 9x - 22 are ( x + 2 ) and ( x - 11 ).
Answer:
-5
Step-by-step explanation:
f(-2) means that -2 is going to be our input in this function.
To solve this, simply substitute -2 for x in the expression given.
If f(x) = 3x+1, then f(-2) = 3(-2) + 1
3(-2)+1 = -6+1 = -5
Hope this helped!
I'm guessing you want an equation.
In that case, the equation would be $2x =y
For number 3 it says
X - 9 for x=-5
X-9 = ___ -9
It gave you your x so you would just substitute and in result you will have an equation of -5 -9
It would give you -14 , since it’s 2 negatives being added ,because you double tapped . Hope this helps :)
Answer:
(f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Step-by-step explanation:
The function f⁻¹(x) is the reflection of the function f(x) across the line y=x. Every point (a, b) that is on the graph of f(x) is reflected to be a point (b, a) on the graph of f⁻¹(x).
Any line with slope m reflected across the line y=x will have slope 1/m. (x and y are interchanged, so m=∆y/∆x becomes ∆x/∆y=1/m) Since f'(x) is the slope of the tangent line at (x, f(x)), 1/f'(x) will be the slope of the tangent line at (f(x), x).
Replacing x with f⁻¹(x) in the above relation, you get ...
... (f⁻¹)'(x) = 1/f'(f⁻¹(x)) will be the slope at (x, f⁻¹(x))
Putting your given values in this relation, you get
... (f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
