The question did not show the original vertices of A, B, and C.
Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:
For A(x, y)
The coordinate of vertex A' will be A' (4x, 4y)
For B(x, y)
The coordinate of vertex B' will be B' (4x, 4y)
For C(x, y)
The coordinate of vertec C' will be C' (4x, 4y)
The result of multiplying 2y (one-fourth y + three-fourths) is one-half y squared + 6 over 4 y
<h3>Multiplication of numbers</h3>
- 2 y (one-fourth y + three-fourths).
2y(1/4y + 3/4)
= (2y × 1/4y) + (2y × 3/4)
= 2/4y² + 6/4y
= 1/2y² + 3/2y
Given options:
= 9/4y + 11/4
= 1/2y + 6/4
- one-half y squared + 6 over 4 y
= 1/2y² + 6/4y
- 9 over 4 y squared + 11 over 4 y
9/4y² + 11/4y
Therefore, the result of multiplying 2y (one-fourth y + three-fourths) is one-half y squared + 6 over 4 y
Learn more on multiplication:
brainly.com/question/10873737
Answer:
T
Step-by-step explanation:
Go to the right 1/4 of a unit and down 1/2 of a unit
The point is T
Answer:
18
Step-by-step explanation:
are you asking for the 9th term or the 10th term?
