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3 years ago

Q4 Prove thatb Tan÷1-Cot +Cot ÷1-tan = 1 + tan + cot =Sec.cosec+1

Mathematics

2 answers:

umka21 [38]3 years ago

8 0

jjkzkzkzkzkzkzkkzkzkzkkzkzkiziz9s9

natta225 [31]3 years ago

6 0

Answer:

I wish I could help but I don't know

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There are 50 cupcakes and 160 cookies to be sold at the school bake sale. What is the greatest number of packages of baked items

Sav [38]

The greatest number of packages of baked items that can be sold is 10

Solution:

Given that there are 50 cupcakes and 160 cookies to be sold at the school bake sale

To find: greatest number of packages of baked items that can be sold

Each package has the same number of cupcakes and same number of cookies with none left over

So, we have to find the greatest common factor of 50 and 160

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

Greatest common factor of 50 and 160:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 160 are: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160

Then the greatest common factor is 10

So the greatest number of packages sold is 10

Each package will contain:

Given that there 50 cupcakes and 160 cookies

Number of cupcakes in 1 package:

$\rightarrow \frac{50}{10} = 5$

Number of cookies in 1 package:

$\rightarrow \frac{160}{10} = 16$

So each package has the same number of cupcakes and same number of cookies with none left over

7 0

3 years ago

What is the Kinetic energy of a 2000 kg bus that is moving at 30m/s? Explain please

agasfer [191]

There's a formula for that.

KE = (1/2)mv²

... = (1/2)(2000 kg)(30 m/s)²

... = 900,000 kg·m²/s²

... = 900,000 J

_____

It is helpful to know the relationship between kilograms, meters, seconds, and Newtons or Joules.

1 J = 1 kg·m²/s²

4 0

3 years ago

Can anyone help me with 2 and 3

Ede4ka [16]

2: 14+15d+9c
3: a.
ignore this I need 20 characters.:)))

3 0

3 years ago

The force, F (Newtons), between two objects is inversely proportional to the square of the distance, d (metres), between them.

snow_lady [41]

Answer:

d = 1.46 m

Step-by-step explanation:

We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:

From the question given above,

F is inversely proportional to square of d. This can be written as:

F ∝ 1/d²

F = K/d²

Cross multiply

K = Fd²

But:

Force (F) = 0.006 N

Distance (d) = 4 m

Constant (K) =?

K = Fd²

K = 0.006 × 4²

K = 0.006 × 16

K = 0.096 Nm²

Therefore, the relationship between the force (F) and the distance (d) is:

F = K/d²

F = 0.096 / d²

Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:

Force (F) = 0.045 N

Constant (K) = 0.096 Nm²

Distance (d) =?

F = K/d²

0.045 = 0.096 / d²

Cross multiply

0.045 × d² = 0.096

Divide both side by 0.045

d² = 0.096 / 0.045

Take the square root of both side.

d = √(0.096 / 0.045)

d = 1.46 m.

7 0

2 years ago

GURRY FOR BRAINLEIST PLS HURRY

pashok25 [27]

Answer:

C= 10.6

Step-by-step explanation:

AB^2=AC^2+CB^2

C^2=7^2+8^2

C^2= 113

√113=10.630

5 0

3 years ago

Q4 Prove thatb Tan÷1-Cot +Cot ÷1-tan = 1 + tan + cot =Sec.cosec+1​

Q4 Prove thatb Tan÷1-Cot +Cot ÷1-tan = 1 + tan + cot =Sec.cosec+1