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ziro4ka [17]
3 years ago
6

What is the formula for slope intercept form?

Mathematics
1 answer:
melisa1 [442]3 years ago
4 0

Answer:

y^2-y^1 over x^2-x^1 is slope intercept form

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What is the length of a segment with endpoints at F(6, 4) and G(14, 19)? Round to the nearest whole number.
Mila [183]

Answer:

17

Step-by-step explanation:

d = √( (x₂ - x₁)² + (y₂ - y₁)² )

   = √( (14 - 6)² + (19 - 4)² )

   = √( 8² + 15² )

   = √( 64 + 225 )

   =  \sqrt{289}

   = 17

4 0
3 years ago
Can someone pls help me the question is in the picture and the answer choices are
Ratling [72]

Sure. We have E(2t,0) and C(2p,2r) so the midpoint M is


M = \frac 1 2(E+C) = ((2t+2p)/2, (0+2r)/2)=(t+p,r)


Choice B



4 0
3 years ago
Find the nth term or this sequence 3 8 13 18 23
netineya [11]
Solutions 
3 8 13 18 23 

The pattern is add 5 each time. 
3 + 5 = 8 
8 + 5 = 13 
13 + 5 = 18 
18 + 5 = 23 
23 + 5 = 28 
28 + 5 = 33
33 + 5 = 38 
38 + 5 = 43 ⇒ The 9th term is 43

43 is the answer 

4 0
4 years ago
Read 2 more answers
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
4 years ago
Solve x2 - 8x - 9 = 0.<br><br> Rewrite the equation so that it is of the form <br> x2 + bx = c.
stira [4]
X^2 - 8x-9=0
D = b^2- 4*a*c = 64- 4* (-9) = 64+36=100 =10^2
X1 = (8-10)/2 = -1
X2= (8+10)/2= 9


7 0
4 years ago
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