Answer:
The ball will take 1 sec
Step-by-step explanation:
∵ The distance from the ground when the ball leaves = 6 ft
∵ The distance from the ground when the ball catches = 10 ft
∴ The difference between two position = 10 - 6 = 4 ft
∵ s = ut - 1/2 at² ⇒ s is the distance , u is the initial velocity , a is acceleration of gravity and t is the time
∵ s = 4 feet , u = 20 feet/sec and a ≅ 32 feet/sec²
∴ 4 = 20t -32/2 t²
∴ 16t² - 20t + 4 = 0
∴ (4t - 4)(4t - 1) = 0
∴ 4t - 4 = 0 ⇒ t = 1 and 4t - 1 = 0 ⇒ t = 1/4
∴ The ball will take 1 sec to go from first player to the second player
Note: 1/4 sec is the time of the ball after leaves the position of the first player by 4 feet above the initial position.
A^2+b^2 = c^2, so 4^2 + 18^2 = 340, the square root of 340 = 18.43909. Rounded to the nearest tenth, the answer is 18.4
Evaluate.
Exact Form:
2/3
Decimal Form:
0.6∞
Hope this helps! :)
Answer:
He needs 31.25 bales of hay to feed 15 horses for two weeks
Step-by-step explanation:
This question can be solved using a rule of three.
25 bales of hay feed 12 horses. How many feed 15 horses?
12 horses - 25 bales of hay
15 horses - x bales of hay
He needs 31.25 bales of hay to feed 15 horses for two weeks
0.92085175 radians
Let's first calculate the length of the diagonal of the base. Using the Pythagorean theorem:
b = sqrt(9^2 + 7^2) = sqrt(81 + 49) = sqrt(130) = 11.40175425
Now the length of the diagonal to the box. Once again, using the Pythagorean theorem:
d = sqrt(15^2 + 11.40175425^2) = sqrt(225 + 130) = sqrt(335) = 18.84144368
We now have a right triangle where we know the lengths of all three sides. The lengths are:
a = 15
b = sqrt(130) ≠11.40175425
c = sqrt(335) ≠18.84144368
we want the angle opposite to side a. So
tan(A) = 15/11.40175425 = 1.315587029
A = atan(1.315587029)
A = 0.92085175 radians
