Supplementary angles sum up to 180°, suppose the supplement of 161° is x. Then
161+x=180
solving for x we subtract 161 from both sides
161-161+x=180-161
x=19
thus the supplement is 19°
Answer:
the equation is : x²-x-12
Step-by-step explanation:
the quadratic equation is in the form of : y=ax²+bx+c
the product of the zeros is -12 and the sum is 1
b = - 1
c=-12 (product)
y=x²-x-12
check : factorize first (x+3)(x-4)=0
either x+3=0 then x=-3
or x-4=0 then x=4
-3*4=-12
-3+4=1
the equation is : x²-x-12
Answer:
C (1,2)
Step-by-step explanation:
The point that is a solution must satisfy both inequalities;
The inequalities are;
Point A
: True
:False
Point B (0,4)
: False
:True
Point C (1,2)
: True
:True
Point D(-2,-4)
: True
:False
The correct answer is C.
-12 + 4 3/5 = -7.4 <--- decimal.
-6 2/7 + 3 1/14 = 3 3/14 <--- repeating decimal.
-2 2/3 + -3 3/4 = -6 5/12 <--- repeating decimal.
°.✩┈┈┈┈∘*┈┈୨♡୧┈┈*∘┈┈┈┈✩.°
I hope this helps you. It kind of helps me because, I wanna scream and cry and just stay in one room. So imma go outside and sit down.. and walk back to my room and scream into a pillow (っ◞‸◟c)
Answer:
4/3
Step-by-step explanation:
If the ratio between the volumes of the first and the second cube is 64, the ratio between the sides is the cubic root of the ratio between the volumes, so:
![s1 / s2 = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=s1%20%2F%20s2%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%20%3D%204)
Doing the same for the second and third cubes, we have:
![s2/ s3 = \sqrt[3]{1/27} = 1/3](https://tex.z-dn.net/?f=s2%2F%20s3%20%3D%20%5Csqrt%5B3%5D%7B1%2F27%7D%20%20%3D%201%2F3)
So the ratio of the first cube side and the third cube side is:
