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svetlana [45]
3 years ago
8

A grocery store sells boxes of two kinds of cereals, wheat-based and rice-based. In this store, the average weight of a box of r

ice-based cereal is 60 ounces, the average weight of a box of wheat-based cereal is 48 ounces, and the average weight of all the boxes of cereal is 50 ounces. What is the ratio in this store of boxes of rice-based cereals to wheat-based cereals?
Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

The ratio of rice-based cereals to wheat-based cereals is 1/5

Step-by-step explanation:

In this problem, we know the weight of both kind of boxes of cereal and also the average weight of the total amount of boxes in the grocery store.

However, we don't know how many boxes of each kind are there in the store and we need to figure out what the ratio is.

Data:

Wheat-based cereal box weight = 48 ounces

Rice-based cereal box weight = 60 ounces

Average weight of total boxes = 50 ounces

Let's name

x= number of wheat-based boxes of cereal.

y=number of rice-based boxes of cereal.

The total weight of the wheat and rice cereals would be 48x+60y

We know that the average weight is a division between the total amount of weight and the amount of items we have, algebraically and based on the previous expression, we would write the equation this way:

\frac{48x+60y}{x+y} =50

Solving the equation we get:

48x+60y=50(x+y)\\ 48x+60y =50x+50y\\ 60y-50y=50x-48x\\ 10y=2x\\ \frac{y}{x}=\frac{2}{10}\\ \frac{y}{x}=\frac{1}{5}

Therefore, the ratio in this store of boxes of rice-based cereals to wheat-based cereals is 1/5

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(a) <em>H</em>₀: <em>μ ≥ 5.70 </em><em>vs. </em><em>Hₐ</em>:<em>μ < 5.70</em>

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Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

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<em>Hₐ</em>: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. <em>μ < 5.70</em><em>.</em>

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Use the <em>t-</em>table for the critical value.

t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c)

The test statistic value is:

t=\frac{\bar x-\mu}{s/\sqrt{n}}

Given:

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Compute the value of the <em>t</em>-statistic as follows:

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The value of the test statistic is -4.33.

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The value of the test is less than the critical value.

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This implies that the test statistic lies in the rejection region.

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As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

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The conditions required for the <em>t-</em>test for single mean to be valid is:

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