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2 years ago

14

Find the area of the rhombus. A= square units

1 answer:

Olin [163]2 years ago

7 0

The answer should be 24 square units.

5 is the hypotenuse and the one we need is the base and the height. They gave us the height, which was 6 in total but 3 for the triangle. But we needed to find the base.

In order to do that, we need to use the Pythagorean Theorem.

a^2+b^2=c^2

3^2+b^2=5^2

9+b^2=25

Subtract 9 from both sides

b^2=16

Then square root both sides.

b=4.

Now that we have the base, you can then find the area of the triangle.

BH/2
4*3/2
12/2
6

So one triangle equals to 6. Then multiply that by 4 to find the area of the rhombus. Which would be 24 square units.

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what is -8x-9=-21, can someone work out the problem and show me what they did to get there answer so i can understand it?

SashulF [63]

- 8x - 9 = - 21

Add 9 to both sides:

- 8x = - 12

Divide both sides by - 8:

x = -12/-8

x = -3/-2

x = 3/2 OR 1.5

Hope this answer helps :)

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2 years ago

Read 2 more answers

4.1(-7.93-4.39a)-4.6a

ki77a [65]

Answer:

−22.599a−32.513

Step-by-step explanation:

Distribute:

= (4.1) (−7.93) + (4.1) (− 4.39 a) + − 4.6 a

= − 32.513 + − 17.999 a + − 4.6 a

Combine Like Terms:

= −32.513 + − 17.999 a + − 4.6 a

= (− 17.999 a + −4.6 a) + (− 32.513)

= − 22.599 a + (− 32.513) = − 22.599 a − 32.513

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2 years ago

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Use completing the square to determine which of the following gives the solutions to 3x2 - 24x + 40 = 28.

jeka94

Answer:

$x=4+2\sqrt{3}$

$x=4-2\sqrt{3}$

Step-by-step explanation:

<u>Completing the square</u>

when $ax^2+bx+c=0$

Given equation:

$3x^2-24x+40=28$

Subtract 40 from both sides:

$\implies 3x^2-24x=-12$

Divide both sides by 3:

$\implies x^2-8x=-4$

Add the square of half the coefficient of $x$ to both sides:

$(\frac{b}{2})^2=(\frac{-8}{2})^2=16$

$\implies x^2-8x+16=-4+16$

Factor the left side and simplify the right side:

$\implies (x-4)^2=12$

Square root both sides:

$\implies x-4=\pm\sqrt{12}$

Add 4 to both sides and simplify the radical:

$\implies x=4\pm\sqrt{4 \cdot 3}$

$\implies x=4\pm\sqrt{4}\sqrt{3}$

$\implies x=4\pm2\sqrt{3}$

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Paha777 [63]

Answer:

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Step-by-step explanation:

1. you should tell me

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