Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
I think the answer is 5700
Answer:
54 students.
Step-by-step explanation:
If you have 600 and 9% the nearest rounding point is %10. %10 of 600 is 60, and 1% of 60 is 6, so 60-6=54.
Answer:
1/72=x (part a)
1/70=x (bart b)
Step-by-step explanation:
Divide 1 by 72 for part a, and divide 1 by 70 for part b.
