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hichkok12 [17]
4 years ago
15

What is the equation of the graphed line?

Mathematics
1 answer:
Rufina [12.5K]4 years ago
7 0
Line<span> crosses the y-axis, b, called the y-intercept. when </span>graphing, put thisequation<span> into "y = " form to easily read </span>graphing<span> information. horizontal</span>lines<span> have a slope of zero - they have "run", but no "rise" -- all of the y values are 3.</span>
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2<br> v<br> What is the equation of a line that is parallel to y = -4x – 3 and shifted down 3 units?
Ugo [173]

Answer: y=-4x-6

Step-by-step explanation:

Given

The equation of line is y=-4x-3

The line which is parallel to the given line is y=-4x+c

and shifted by 3 units down i.e. its y-intercept is 3 units below the given line

\therefore y=-4x-3-3\\\Rightarrow y=-4x-6

3 0
3 years ago
Select all expressions that are equivalent to 6x+1-(3x-1).
klio [65]

Answer:6x+1-3x-1

negative and negative= positive

3x+2

answer: 3x+2

Step-by-step explanation:

3 0
3 years ago
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Angel ate 2/3 of the chicken wings that were on the platter. How many chicken wings were on the platter if he ate 8 wings?
borishaifa [10]

Answer:

12

Step-by-step explanation:2/3 of 12 =8


3 0
4 years ago
A baby's crib has an area of 690:square inches and a perimeter of 106 inches.What are the dimensions of the crib
KengaRu [80]

Answer:

The crib is 30 inches wide and 23 inches long.

Step-by-step explanation:

Assuming that the crib is rectangular, then the crib has a length L and a width W.

And remember that for a rectangle of width W and length L, the perimeter is:

P = 2*L + 2*W = 2*(L + W)

And the area is:

A = L*W

In this case, the perimeter is 106 in, then:

P = 106in = 2*(L + W)

And we also know that the area is 690 in^2

Then:

A = 690in^2 = L*W

Then we have a system of equations:

106in = 2*(L + W)

690in^2 = L*W

To solve this, first, we need to isolate one of the variables in one of the equations.

Let's isolate L in the first one:

106in/2 = L + W

53 in = L + W

53in - W = L

Now we can replace this in the other equation:

690in^2 = L*W = (53in - W)*W = 53in*W - W^2

690in^2 =  53in*W - W^2

Now we need to solve this for W.

This is a quadratic equation:

W^2 - 53in*W + 690 in^2 = 0

The solutions of this equation are given by Bhaskara's formula:

W = \frac{-(-53in)\pm \sqrt{(-53in)^2 - 4*1*(690in^2)}  }{2} =  \frac{57in \pm 7in}{2}

Then the two possible solutions of W are:

W = (53in + 7in)/2 = 30in

W = (53in - 7in)/2 = 23in

We can choose any one of these, so let's choose W = 30in

If we replace this in the equation: "53in - W = L"

We can find the value of L:

53in - 30in = 23in = L

Then we have:

W = 30in

L = 23in

4 0
3 years ago
OVER HERE WALKER.
ziro4ka [17]

Answer:

5 bars

Step-by-step explanation:

6 0
3 years ago
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