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3 years ago

15

Simplify (-6)^-3 and explain

2 answers:

nata0808 [166]3 years ago

4 0

Ok so in this problem we will use some laws that relate to exponents.

x^-1 = 1/x this is the law we will use in this case.

-6^(-3) simplified is 1/-6^3 then from there evaluate -6^3, which is -216.

So the final answer is 1/-216

gizmo_the_mogwai [7]3 years ago

3 0

So basically we are multiplying the number -6 3 times they are trying to trick you. BUT a tip is to think of it as regular multiplication and then applying that to exponents. So first multiply 6 times 6 whixh is 36 times 6 which is 216 so 1/216 should be your final answer.

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2 years ago

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DedPeter [7]

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8 0

3 years ago

Quick algebra 1 question for 10 points!

valina [46]

<u>Answer:</u>

○ 1 hour 41 minutes or more

<u>Step-by-step explanation:</u>

We can make two equations that represent the total amount each plumber charges.

If $x$ represents the number of hours they work, then:

•Total charged by Plumber A = $35 + 15x$

• Total charged by Plumber B = $40+12x$

Now, if Plumber A is more expensive than Plumber B, then:

Total charged by Plumber A > Total charged by Plumber B

∴ $35 + 15x$ > $40+12x$

Now all we have to do is solve for $x$ :

$35 + 15x$ > $40+12x$

⇒ $35 + 15x -12x > 40$

⇒ $35 + 3x > 40$

⇒ $3x > 5$

⇒ $x > \bf \frac{5}{3} \space\ \mathrm{h}$

$\frac{5}{3} \space\ \mathrm h$ is equivalent to $\frac{5}{3} \times 60 \space\ \mathrm {min}$ = 100 minutes, which is the same as 1h 40min.

This means if Plumber A works more than 1h 40min, they become more expensive than Plumber B.

More than 1h 40min is equivalent to '1 hour 41 minutes or more', therefore the first option is correct.

4 0

1 year ago